https://www.course-notes.org/chemistry/topic_notes/aqueous_solutions_and_solution_chemistry/solution_concentrationstoichiometry |
Monday, January 25, 2016
Quiz Reflection
Our final lecture of the unit aqueous solutions was how to tie molarity to our stoichometry calculations we have learned in previous units. It seems like all of chemistry somehow leads back to Stoich... Anyways, we learned how to find grams, volume, moles, or molarity of a substance, using molarity (mol per 1L) as a conversion factor. We can use molarity to get from volume to moles, and then subsequently from moles to grams, and vice versa.
Murder Lab Day 2
Day Two consisted of weighing the dry filter paper that contained the solid from the reaction. The solid was a pea green powder. After weighing the filter paper, we subtracted this mass from the mass of just the filter paper to figure out the mass of the solid. Then, we calculated the molarity of this substance and found out that it was roughly 0.07 M. To figure out the identity of the unknown substance, we knew that it must have been silver nitrate because when silver nitrate combines with sodium carbonate, it should make a solid, which is exactly what happened in lab. The 0.07 molarity matched Mr. Green's description, as he was found with traces of silver nitrate with a molarity between 0.05 and 0.15 M.
Murder Lab Day 1
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